Question: A and B together can do a work in 10 days. B and C together can do the same work in 6 days. A and C together can do the work in 12 days. Then, A, B and C together can do the work in
Options:
A) $ 28days $
B) $ 14days $
C) $ 5\frac{5}{7}days $
D) $ 8\frac{2}{7}days $
Show Answer
Answer:
Correct Answer: C
Solution:
- Given, (A + B)’s 1 day’s work $ =\frac{1}{10} $
(i)
(B + C)‘s1 day’s works $ =\frac{1}{6} $ … (ii)
(C + A)’s 1 day’s work $ =\frac{1}{12} $
(iii)
On adding Eqs. (i), (ii) and (iii), we get
2 (A + B + C)’s 1 day’s work $ =\frac{1}{10}+\frac{1}{6}+\frac{1}{12} $
$ =\frac{6+10+5}{60}=\frac{21}{60}=\frac{7}{20} $
$ \Rightarrow $ (A + B + C)’s 1 day’s work $ =\frac{7}{40} $
$ \therefore $ All three together will complete the work in
$ =\frac{40}{7}=5\frac{5}{7}days $