SATHEE: Quantitative Aptitude Ques 1670

Quantitative Aptitude Ques 1670

Question: Directions: In these questions two equations numbered I and II are given. You have to solve both the equations and give answer. [IBPS (SO) 2014]

I. $ x^{2}+5x+6=0 $
II. $ 4y^{2}+24y+35=0 $

Options:

A) If $ x>y $

B) If $ x\le y $

C) If $ x<y $

D) If $ x\ge y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: E

Solution:

I. $ x^{2}+5x+6=0 $

$ \Rightarrow $ $ x^{2}+3x+2x+6=0 $

$ \Rightarrow $ $ x(x+3)+2(x+3)=0 $

$ \Rightarrow $ $ (x+2)(x+3)=0 $

$ \therefore $ $ x=-2, $ $ -3 $ II. $ 4y^{2}+24y+35=0 $

$ \Rightarrow $ $ 4y^{2}+14y+10y+35=0 $

$ \Rightarrow $ $ 2y(2y+7)+5(2y+7)=0 $

$ \Rightarrow $ $ (2y+5)(2y+7)=0 $

$ \therefore $ $ y=-\frac{5}{2}, $ $ -\frac{7}{2} $ Hence, relationship between x and y cannot be established.

Quantitative Aptitude Ques 1669

Quantitative Aptitude Ques 1671

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