Quantitative Aptitude Ques 1639

Question: Directions: In the following questions, two equations numbered I and II have been given. You have to solve both the equations and mark the correct answer. [SBI (PO) 2015]

I. $ 3x^{2}+29x+56=0 $ II. $ 2y^{2}+15y+25=0 $

Options:

A) lf $ x<y $

B) If $ x>y $

C) If $ x\ge y $

D) If $ x\le y $

E) If relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: A

Solution:

  • [a] I. $ 3x^{2}+29x+56=0 $

$ \Rightarrow $ $ 3x^{2}+21x+8x+56=0 $

$ \Rightarrow $ $ 3x,(x+7)+8,(x+7)=0 $

$ \Rightarrow $ $ (3x+8)(x+7)=0\Rightarrow x=-7, $ $ -\frac{8}{3} $ II. $ 2y^{2}+15y+25=0 $

$ \Rightarrow $ $ 2y^{2}+10y+5y+25=0 $

$ \Rightarrow $ $ 2y,(y+5)+5,(y+5)=0 $

$ \Rightarrow $ $ (y+5)(2y+5)=0\Rightarrow y=-5, $ $ -\frac{5}{2} $ Hence, $ y>x $