SATHEE: Quantitative Aptitude Ques 163

Quantitative Aptitude Ques 163

Question: A trader sold a pen at a loss of 20%. If he sells the pen at Rs. 12 more he would have gained 10%. The cost price of the pen (in Rs.) is

Options:

A) 60

B) 40

C) 30

D) 22

Show Answer

Answer:

Correct Answer: B

Solution:

Let the CP of the pen be x. Then, selling price $ =100\times \frac{(x-20)}{100}=\frac{4x}{5} $ According to the question, $ \frac{4x}{5}+12=x+\frac{10}{100}\times x $

$ \Rightarrow $ $ \frac{4x}{5}\times 12=\frac{11x}{10} $
$ \Rightarrow $ $ 12=\frac{11x}{10}-\frac{4x}{5} $

$ \Rightarrow $ $ 12=\frac{11x-8x}{10} $
$ \Rightarrow $ $ \frac{120}{3}=x $

$ \Rightarrow $ $ x=Rs.,40 $

BETA

Privacy Policy

Powered by Prutor@IITK

sathee@iitk.ac.in

Media coverage of SATHEE

Play Store

App Store

The Ministry of Education has launched the SATHEE initiative in association with IIT Kanpur to provide free guidance for competitive exams. SATHEE offers a range of resources, including reference video lectures, mock tests, and other resources to support your preparation. Please note that participation in the SATHEE program does not guarantee clearing any exam or admission to any institute.

Quantitative Aptitude Ques 163

Question: A trader sold a pen at a loss of 20%. If he sells the pen at Rs. 12 more he would have gained 10%. The cost price of the pen (in Rs.) is

Options:

Answer:

Solution:

Bank Preparation

Bank Courses

NCERT Books

Important Resources

Forum