SATHEE: Quantitative Aptitude Ques 1578

Quantitative Aptitude Ques 1578

Question: 20 L of a mixture contains 20% alcohol and the rest water. If 4 L of water be mixed in it, the percentage of alcohol in the new mixture, will be

Options:

A) $ 33\frac{1}{3} $ %

B) $ 16\frac{2}{3} $ %

C) $ 25 $ %

D) $ 12\frac{1}{2} $ %

Show Answer

Answer:

Correct Answer: B

Solution:

Amount of alcohol in 20 L of mixture $ =20%\text{of 20}\text{L=}\frac{20\times 20}{100}=4L $

$ \therefore $ Water in the mixture $ =20-4=16L $ Now, 4 L of water is further added

$ \therefore $ Amount of water $ =16+4=20L $

$ \therefore $ Percentage of alcohol in new mixture $ =\frac{Amountofalcohol}{Totalmixture}\times 100% $ $ =\frac{4}{24}\times 100=\frac{100}{6} $ % $ =\frac{50}{3} $ % $ =16\frac{2}{3} $ %

Quantitative Aptitude Ques 1577

Quantitative Aptitude Ques 1579

Quantitative Aptitude Ques 1578

Question: 20 L of a mixture contains 20% alcohol and the rest water. If 4 L of water be mixed in it, the percentage of alcohol in the new mixture, will be

Options:

Answer:

Solution:

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