Quantitative Aptitude Ques 1577
Options:
A) $ 96cm^{2} $
B) $ 192cm^{2} $
C) $ 288cm^{2} $
D) $ 374cm^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Semi-perimeter,
$ s=\frac{18+24+30}{2}=\frac{72}{2}=36cm $
Now, area of triangle $ =\frac{4}{3}\sqrt{s(s-u)(s-v)(s-w)} $
$ =\frac{4}{3}\sqrt{36(36-18)(36-24)(36-30)} $
$ =\frac{4}{3}\sqrt{36\times 18\times 12\times 6} $
$ =\frac{4}{3}\times 6\times 3\times 2\times 2\times 3 $
$ =24\times 12=288cm^{2} $