Quantitative Aptitude Ques 1577
Question: The medians AD, BE and CF of a $ \Delta ABC $ are of lengths of $ 18cm, $ $ 24cm $ and $ 30cm, $ respectively. The area $ (incm^{2}) $ of the triangle is
Options:
A) $ 96cm^{2} $
B) $ 192cm^{2} $
C) $ 288cm^{2} $
D) $ 374cm^{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Semi-perimeter, $ s=\frac{18+24+30}{2}=\frac{72}{2}=36cm $ Now, area of triangle $ =\frac{4}{3}\sqrt{s(s-u)(s-v)(s-w)} $ $ =\frac{4}{3}\sqrt{36(36-18)(36-24)(36-30)} $ $ =\frac{4}{3}\sqrt{36\times 18\times 12\times 6} $ $ =\frac{4}{3}\times 6\times 3\times 2\times 2\times 3 $ $ =24\times 12=288cm^{2} $
BETA
