Question: Two pipes A and B can fill a tank in 36 min and 45 min, respectively. Another pipe C can empty the tank in 30 min. First A and B are opened. After 7 min, C is also opened. The tank is filled up in
Options:
A) 39 min
B) 46 min
C) 40 min
D) 46 min
Show Answer
Answer:
Correct Answer: A
Solution:
- Work done by pipes A and B in 1 min
$ =\frac{1}{36}+\frac{1}{45}=\frac{5+4}{180}=\frac{9}{180}=\frac{1}{20} $
Work done by pipes A and B in 7 min $ =\frac{7}{20} $
Left work $ =1-\frac{7}{20}=\frac{13}{20} $
Now, work done by pipes A, B and C in 1 min
$ =\frac{1}{36}+\frac{1}{45}-\frac{1}{30}=\frac{5+4-6}{180}=\frac{3}{180}=\frac{1}{60} $
$ \therefore $ Work done by A, B and C in x min = Left work
$ \Rightarrow $ $ x\times \frac{1}{60}=\frac{13}{20} $
$ \Rightarrow $ $ x=\frac{13}{20}\times 60=39\min $