Quantitative Aptitude Ques 1573

Question: Two pipes A and B can fill a tank in 36 min and 45 min, respectively. Another pipe C can empty the tank in 30 min. First A and B are opened. After 7 min, C is also opened. The tank is filled up in

Options:

A) 39 min

B) 46 min

C) 40 min

D) 46 min

Show Answer

Answer:

Correct Answer: A

Solution:

  • Work done by pipes A and B in 1 min $ =\frac{1}{36}+\frac{1}{45}=\frac{5+4}{180}=\frac{9}{180}=\frac{1}{20} $ Work done by pipes A and B in 7 min $ =\frac{7}{20} $ Left work $ =1-\frac{7}{20}=\frac{13}{20} $ Now, work done by pipes A, B and C in 1 min $ =\frac{1}{36}+\frac{1}{45}-\frac{1}{30}=\frac{5+4-6}{180}=\frac{3}{180}=\frac{1}{60} $

$ \therefore $ Work done by A, B and C in x min = Left work

$ \Rightarrow $ $ x\times \frac{1}{60}=\frac{13}{20} $
$ \Rightarrow $ $ x=\frac{13}{20}\times 60=39\min $