Quantitative Aptitude Ques 1540
Question: A train running at $ 8/11km/h $ of its own speed reached a place in $ 5\frac{1}{2}h. $ How much time could be saved, if the train would have run at it own speed?
Options:
A) $ 2\frac{1}{2}h $
B) $ 2h $
C) $ 1\frac{1}{2}h $
D) $ 1h $
Show Answer
Answer:
Correct Answer: C
Solution:
- (c) New speed $ =\frac{8}{11} $ of usual speed.
$ \therefore $ New time $ =\frac{11}{8} $ of. usual time. So, $ \frac{11}{8} $ of usual time $ =\frac{11}{2}h $
$ \Rightarrow $ Usual time $ =\frac{11\times 8}{2\times 11}=4h $ Hence, time saved $ =5\frac{1}{2}-4=1\frac{1}{2}h $ .
BETA
