Quantitative Aptitude Ques 1540

Question: A train running at $ 8/11km/h $ of its own speed reached a place in $ 5\frac{1}{2}h. $ How much time could be saved, if the train would have run at it own speed?

Options:

A) $ 2\frac{1}{2}h $

B) $ 2h $

C) $ 1\frac{1}{2}h $

D) $ 1h $

Show Answer

Answer:

Correct Answer: C

Solution:

  • (c) New speed $ =\frac{8}{11} $ of usual speed.

$ \therefore $ New time $ =\frac{11}{8} $ of. usual time. So, $ \frac{11}{8} $ of usual time $ =\frac{11}{2}h $

$ \Rightarrow $ Usual time $ =\frac{11\times 8}{2\times 11}=4h $ Hence, time saved $ =5\frac{1}{2}-4=1\frac{1}{2}h $ .

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