Quantitative Aptitude Ques 1531

Question: Directions: In these given questions two equations are given. You have to solve both the equations and give answer. [IBPS RRB (Office Assistant) 2014]

I. $ 2x^{2}+18x+40=0 $
II. $ 2y^{2}+15y+27=0 $

Options:

A) If $ x\le y $

B) If $ x>y $

C) If $ x<y $

D) If $ x\ge y $

E) If $ x=y $ or relationship cannot be established

Show Answer

Answer:

Correct Answer: E

Solution:

  • (e) I. $ 2x^{2}+18x+40=0 $

$ \Rightarrow $ $ 2x^{2}+10x+8x+40=0 $

$ \Rightarrow $ $ 2x(x+5)+8(x+5)=0 $

$ \Rightarrow $ $ (2x+8)(x+5)=0 $

$ \therefore $ $ x=-4, $ $ x=-5 $ II. $ 2y^{2}+15y+27=0 $

$ \Rightarrow $ $ 2y^{2}+9y+6y+27=0 $

$ \Rightarrow $ $ y(2y+9)+3(2y+9)=0 $

$ \Rightarrow $ $ (y+3)(2y+9)=0 $

$ \therefore $ $ y=-3, $ $ y=-\frac{9}{2} $ Here, relationship cannot be established.