Quantitative Aptitude Ques 1507

Question: In a mixture of 240 cc, the ratio of the volumes of water and glycerine is 1: 3. The quantity of water (in cc) that should be added to the mixture, so that the new ratio of the volumes of water and glycerine becomes 2 : 3, is

Options:

A) 55 cc

B) 60 cc

C) 62.5 cc

D) 64 cc

Show Answer

Answer:

Correct Answer: B

Solution:

  • (b) Given, total mixture $ =240cc $ Ratio of water and glycerin $ =1:3 $ Let the quantity of water be x and quantity of glycerin $ =3x $ Then, $ x+3x=240 $

$ \Rightarrow $ $ 4x=240 $
$ \Rightarrow $ $ x=60 $

$ \therefore $ Quantity of water $ =60cc $ and quantity of glycerin $ =3x=3\times 60=180,cc $ Now, according to the question, New ratio of water and glycerin $ =2:3 $ Let x (cc) of water be added to make the required ratio. Then, $ \frac{60+x}{180}=\frac{2}{3} $

$ \Rightarrow $ $ 180+3x=360 $
$ \Rightarrow $ $ 3x=180 $

$ \Rightarrow $ $ x=\frac{180}{3} $
$ \Rightarrow $ $ x=60,cc $