Question: Pradeep invested 20% more than Mohit. Mohit invested 10% less than Raghu. If the total sum of their investment is Rs. 17880, then how much amount did Raghu invest? [Corporation Bank (PO) 2011]
Options:
A) Rs. 6000
B) Rs. 8000
C) Rs. 7000
D) Rs. 5000
E) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- Let the amount Raghu invested be Rs. x.
Then, amount invested by Mohit $ =x\times \frac{90}{100}=\frac{9x}{10} $
Now, amount invested by Pradeep
$ =\frac{9x}{10}\times \frac{120}{100}=\frac{108x}{100}=\frac{27x}{25} $
$ \therefore $ $ x+\frac{9x}{10}+\frac{27x}{25}=Rs\text{. 17880} $
$ \Rightarrow $ $ \frac{100x+90x+108x}{100}=17880 $
$ \Rightarrow $ $ 298x=17880\times 100 $
$ \Rightarrow $ $ x=\frac{17880\times 100}{298} $
$ \therefore $ $ x=60\times 100=Rs\text{. 6000} $