Quantitative Aptitude Ques 1494
Question: If the point $ (x,y) $ is equidistant from par $ (7,1) $ and $ (3,5), $ find $ (x-y). $
Options:
A) 2
B) 4
C) 6
D) 8
E) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
- Let p $ (x,y) $ be equidistant from point A (7, 1) and B (3, 5). $ AP=BP $ So, $ AP^{2}=BP^{2} $
$ \therefore $ $ {{(x-7)}^{2}}+{{(y-1)}^{2}}={{(x-3)}^{2}}+{{(y-5)}^{2}} $
$ \Rightarrow $ $ x^{2}-14x+49+y^{2}-2y+1=x^{2}-6x $ $ +9+y^{2}-10y+25 $
$ \Rightarrow $ $ (x-y)=2 $
BETA
