Quantitative Aptitude Ques 1472

Question: The length of the three sides of a right angled triangle are $ (x-2)cm, $ $ x $ and $ (x+2)cm, $ respectively. Then, the value of $ x $ is

Options:

A) 10

B) 8

C) 4

D) 0

Show Answer

Answer:

Correct Answer: B

Solution:

  • In a right angled $ \Delta ABC, $ By Pythagoras theorem $ ABC, $
    $ {{\text{(Hypotenuse)}}^{2}}={{\text{(Base)}}^{2}}+{{\text{(Perpendicular)}}^{2}} $ $ AC^{2}=AB^{2}+BC^{2} $

$ \Rightarrow $ $ {{(x+2)}^{2}}={{(x-2)}^{2}}+x^{2} $

$ \Rightarrow $ $ x^{2}+4x+4=x^{2}-4x+4+x^{2} $

$ \Rightarrow $ $ x^{2}-8x=0 $

$ \Rightarrow $ $ x(x-8)=0 $

$ \Rightarrow $ $ x=8 $