Question: The length of the three sides of a right angled triangle are $ (x-2)cm, $ $ x $ and $ (x+2)cm, $ respectively. Then, the value of $ x $ is
Options:
A) 10
B) 8
C) 4
D) 0
Show Answer
Answer:
Correct Answer: B
Solution:
- In a right angled $ \Delta ABC, $
By Pythagoras theorem $ ABC, $
$ {{\text{(Hypotenuse)}}^{2}}={{\text{(Base)}}^{2}}+{{\text{(Perpendicular)}}^{2}} $
$ AC^{2}=AB^{2}+BC^{2} $
$ \Rightarrow $ $ {{(x+2)}^{2}}={{(x-2)}^{2}}+x^{2} $
$ \Rightarrow $ $ x^{2}+4x+4=x^{2}-4x+4+x^{2} $
$ \Rightarrow $ $ x^{2}-8x=0 $
$ \Rightarrow $ $ x(x-8)=0 $
$ \Rightarrow $ $ x=8 $