SATHEE: Quantitative Aptitude Ques 1471

Quantitative Aptitude Ques 1471

Question: Two workers A and B working together complete the job in 5 days. If A worked twice as efficiently as he actually did and B worked 1/3 as efficiently as he actually did, the work would have been completed in 3 days. To complete the job alone, A would require

Options:

A) $ 5\frac{1}{2}days $

B) $ 6\frac{1}{4}days $

C) (c) $ 7\frac{1}{2}days $

D) $ 8\frac{3}{4}days $

Show Answer

Answer:

Correct Answer: B

Solution:

Let A and B complete the job in x and y days, respectively. Then, $ \frac{1}{x}+\frac{1}{y}=\frac{1}{5} $ (i) After changing efficiencies, A would be able to completed the work in $ \frac{x}{2} $ days and B in 3y days.

$ \therefore $ $ \frac{2}{x}+\frac{1}{3y}=\frac{1}{3} $ (ii) Solving Eqs. (i) and (ii), we get $ x=\frac{25}{4}=6\frac{1}{4}days $

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