Question: In a mixture of 60 L the ratio of acid and water is 2: 1. If the ratio of acid and water is to be 1: 2, then the amount of water (in litres) to be added to the mixture is
Options:
A) 55
B) 60
C) 60
D) 45
Show Answer
Answer:
Correct Answer: B
Solution:
- Quantity of acid in the mixture $ =\frac{2}{3}\times 60=40L $
Quantity of water $ =60-40=20L $
Let required quantity of water $ =xL $
$ \therefore $ $ \frac{40}{20+x}=\frac{1}{2} $
$ \Rightarrow $ $ 80=20+x $
$ \Rightarrow $ $ x=60L $