Quantitative Aptitude Ques 143
Question: In trapezium ABCD, $ AB\parallel CD $ and AB = 2 CD. Its diagonals intersect at O. If the area of $ \Delta AOB $ is $ 84,cm^{2}, $ then the area of $ \Delta COD $ is
Options:
A) $ 42cm^{2} $
B) $ 72cm^{2} $
C) $ 26cm^{2} $
D) $ 21cm^{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
- Let CD be x.
$ \therefore $ AB = 2x Now, $ \frac{Area,of,\Delta AOB}{Area,of,\Delta COB}=\frac{AB^{2}}{CD^{2}} $
$ \Rightarrow $ $ \frac{84}{Area,of,\Delta COD}=\frac{4x^{2}}{x^{2}} $
$ \therefore $ Area of $ \Delta COD=\frac{84}{4}=21,cm^{2} $
BETA
