Question: The value of $ {{(64)}^{\frac{1}{6}}}\times {{( \frac{3}{2} )}^{4}}\div {{(121)}^{0}}+{{( \frac{1}{3} )}^{4}}, $ is equal to
Options:
A) $ 24 $
B) $ 32 $
C) $ \frac{161}{648} $
D) $ \frac{6569}{648} $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ {{(64)}^{\frac{1}{6}}}\times {{( \frac{3}{2} )}^{4}}\div {{(121)}^{0}}+{{( \frac{1}{3} )}^{4}} $
$ ={{(2)}^{6\times \frac{1}{6}}}\times \frac{81}{16}\times \frac{1}{1}+{{( \frac{1}{3} )}^{4}} $
$ =(2)\times \frac{81}{16}\times 1+\frac{1}{81} $
$ =\frac{81}{8}+\frac{1}{81} $
$ \Rightarrow $ $ \frac{{{(81)}^{2}}+8}{648}=\frac{6561+8}{648}=\frac{6569}{648} $