Quantitative Aptitude Ques 1388
Question: A shopkeeper labelled the price of his articles, so as to earn a profit of 30% on the cost price. Then, he sold the articles by offering a discount of 10% on the labelled price. What is the actual per cent profit earned in the deal? [SBI (PO) 2011]
Options:
A) 18
B) 15
C) 20
D) Cannot be determined
E) None of the above
Show Answer
Answer:
Correct Answer: E
Solution:
- Let the cost price of the article be Rs. x
$ \therefore $ Labelled or Marked price $ =Rs\text{.}x( \frac{100+30}{100} )=Rs\text{. }\frac{13x}{10} $ Now, from the question, Selling price of the article $ =Rs\text{. }\frac{13x}{10}( \frac{100-10}{100} ) $ $ \text{=Rs}\text{. }\frac{13x}{10}\times \frac{9}{10}=Rs\text{. }\frac{117x}{100} $
$ \therefore $ Required per cent profit earned $ =\frac{\frac{117x}{100}-\frac{x}{1}}{x}\times 100 $ $ =\frac{17x}{100x}\times 100=17% $
BETA
