SATHEE: Quantitative Aptitude Ques 137

Quantitative Aptitude Ques 137

Question: A man covers a certain distance on scooter. Had he moved 3 km/h faster, he would have taken 40 min less. If he had moved 2 km/h slower, he would have taken 40 min more. The distance (in km) is

Options:

A) 42.5

B) 36

C) 37.5

D) 40

Show Answer

Answer:

Correct Answer: D

Solution:

Let distance and original speed of the man be d km and s km/h. Then, $ \frac{d}{s}-\frac{d}{s+3}=\frac{2}{3} $

$ \Rightarrow $ $ \frac{d,(s+3-s)}{s,(s+3)}=\frac{2}{3} $

$ \Rightarrow $ $ 9d=2s,(s+3) $ … (i) and $ \frac{d}{s-2}-\frac{d}{s}=\frac{2}{3} $

$ \Rightarrow $ $ \frac{d,(s-s+2)}{s,(s-2)}=\frac{2}{3} $

$ \Rightarrow $ $ 3d=s(s-2) $ (ii) From Eqs. (i) and (ii), we get $ 3s,(s-2)=2s,(s+3) $

$ \Rightarrow $ $ 3s^{2}-6s=2s^{2}+6s $
$ \Rightarrow $ $ s^{2}=12s $

$ \therefore $ $ s=12 $ From Eq. (ii), we get $ 3d=12,(12-2) $

$ \therefore $ $ d=40,km $

Quantitative Aptitude Ques 136

Quantitative Aptitude Ques 138

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