Quantitative Aptitude Ques 1328

Question: Three taps A, B and C can fill a tank in 12, 15 and 20 h, respectively. If A is open all the time and B and C are open for one hour each alternately, then the tank will be filled in

Options:

A) 6 h

B) 7 h

C) 5 h

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • Filling done by pipe A and Bin 1 h $ =\frac{1}{12}+\frac{1}{15}=\frac{3}{20} $ Filling done by pipe A and C in 1 h $ =\frac{1}{12}+\frac{1}{20}=\frac{2}{15} $ Filling done in $ 2h=\frac{3}{20}+\frac{2}{15}=\frac{17}{60} $ Filling done in $ 6h=\frac{17}{60}\times 3=\frac{51}{60} $ Remaining filling $ =1-\frac{51}{60}=\frac{3}{20} $ Now, in 7 h filling done by A and B So, $ time=\frac{\frac{3}{20}}{\frac{3}{20}}=1h $

$ \therefore $ Total time $ =7h $

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