Question: There are two containers of equal capacity. The ratio of milk to water in the first container is 3: 1, in the second container is 5: 2. If they are mixed up, then the ratio of milk to water in the mixture will be
Options:
A) 28 : 41
B) 41 : 28
C) 15 : 41
D) 41 : 15
Show Answer
Answer:
Correct Answer: D
Solution:
- Part of milk in first container $ =\frac{3}{3+1}=\frac{3}{4} $
Part of water in first container $ =\frac{1}{3+1}=\frac{1}{4} $
Similarly, part of milk in second container $ =\frac{5}{5+2}=\frac{5}{7} $
Part of water in second container $ =\frac{2}{5+2}=\frac{2}{7} $
$ \therefore $ Required ratio of milk to water when these mixture are mixed together
$ \frac{\frac{3}{4}+\frac{5}{7}}{\frac{1}{4}+\frac{2}{7}}=\frac{\frac{21+20}{28}}{\frac{7+8}{28}} $
$ =\frac{41}{28}\times \frac{28}{15}=\frac{41}{15}=41:15 $