Quantitative Aptitude Ques 1293

Question: Directions: In the following questions, two equations numbered I and II have been given. You have to solve both the equation and mark the correct answer. [IBPS (PO) Pre 2011]

I. $ 3x^{2}+29x+56=0 $
II. $ 2y^{2}+15y+25=0 $

Options:

A) $ x<y $

B) $ x>y $

C) $ x\ge y $

D) $ x\le y $

E) Relationship between x and y cannot be Established

Show Answer

Answer:

Correct Answer: A

Solution:

  • I. $ 3x^{2}+29x+56=0 $

$ \Rightarrow $ $ =3x^{2}+21x+8x+56=0 $

$ \Rightarrow $ $ 3x,(x+7)+8(x+7)=0 $

$ \Rightarrow $ $ (3x+8)(x+7)=0 $

$ \Rightarrow $ $ x=-7, $ $ x=-\frac{8}{3} $ II. $ 2y^{2}+15y+25=0 $

$ \Rightarrow $ $ 2y^{2}+10y+5y+25=0 $

$ \Rightarrow $ $ 2y(y+5)+5(y+5)=0 $

$ \Rightarrow $ $ (y+5)(2y+5)=0 $

$ \Rightarrow $ $ y=-5, $ $ y=-\frac{5}{2} $

$ \therefore $ $ y>x $