Quantitative Aptitude Ques 128

Question: Directions: In the following question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [IBPS (Officer Recruitment) 2015]

Give answer I. $ 5x^{2}+29x+20=0 $ II. $ 25y^{2}+25y+6=0 $

Options:

A) if $ x\ge y $

B) if $ x\le y $

C) if $ x<y $

D) if $ x>y $

E) if relationship between x and y cannot be established

Show Answer

Answer:

Correct Answer: C

Solution:

  • I. $ 5x^{2}+29x+20=0 $

$ \Rightarrow $ $ 5x^{2}+25x+4x+20=0 $

$ \Rightarrow $ $ 5x,(x+5)+4,(x+5)=0 $

$ \Rightarrow $ $ (5x+4)(x+5)=0 $
$ \Rightarrow $ $ x=-,5 $ or $ \frac{-4}{5} $ II. $ 25y^{2}+25y+6=0 $

$ \Rightarrow $ $ 25y^{2}+15y+10y+6=0 $

$ \Rightarrow $ $ 5y,(5y+3)+2,(5y+3)=0 $

$ \Rightarrow $ $ (5y+2)(5y+3)=0 $
$ \Rightarrow $ $ y=\frac{-,3}{5} $ or $ \frac{-,2}{5} $ Hence, x < y