Quantitative Aptitude Ques 1279

Question: If $ \frac{a}{1-a}+\frac{b}{1-b}+\frac{c}{1-c}=1, $ then the value of $ \frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c} $

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: D

Solution:

  • Given, $ \frac{a}{1-a}+\frac{b}{1-b}+\frac{c}{1-c}=1 $ … (i) On adding 3 in Eq, (i) on both sides, we get $ ( \frac{a}{1-a}+1 )+( \frac{b}{1-b}+1 )+( \frac{c}{1-c}+1 )=3+1=4 $

$ \Rightarrow $ $ \frac{a+1-a}{1-a}+\frac{b+1-b}{1-b}+\frac{c+1-c}{1-c}=4 $

$ \therefore $ $ \frac{1}{1-a}+\frac{1}{1-b}+\frac{1}{1-c}=4 $

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