Quantitative Aptitude Ques 1271

Question: If ABCD be a cyclic quadrilateral in which $ \angle A=4x{}^\circ , $ $ \angle B=7x{}^\circ , $ $ \angle C=5y{}^\circ , $ $ \angle D=y{}^\circ , $ then $ x:y $ is

Options:

A) 3 : 4

B) 4 : 3

C) 5 : 4

D) 4 : 5

Show Answer

Answer:

Correct Answer: B

Solution:

  • In a cyclic quadrilateral. Sum of opposite angle $ =180{}^\circ $ So, $ 4x+5y=7x+y=180{}^\circ $

$ \Rightarrow $ $ 4x+5y=7x+y $

$ \Rightarrow $ $ 5y-y=7x-4x $

$ \Rightarrow $ $ 4y=3x $
$ \Rightarrow $ $ \frac{4}{3}=\frac{x}{y} $

$ \therefore $ $ x:y=4:3 $