Quantitative Aptitude Ques 127
Question: Directions: In the following question, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. [IBPS (Officer Recruitment) 2015]
Give answer I. $ x^{2}-3x-88=0 $ II. $ y^{2}+8y-48=0 $
Options:
A) if $ x\ge y $
B) if $ x\le y $
C) if $ x<y $
D) if $ x>y $
E) if relationship between x and y cannot be established
Show Answer
Answer:
Correct Answer: D
Solution:
- I. $ x^{2}-3x-88=0 $
$ \Rightarrow $ $ x^{2}-11x+8x-88=0 $
$ \Rightarrow $ $ x,(x-11)+8,(x-11)=0 $
$ \Rightarrow $ $ (x+8)(x-11)=0 $
$ \Rightarrow $ $ x=-,8,or,11 $ II. $ y^{2}+8y-48=0 $
$ \Rightarrow $ $ y^{2}+12y-4y-48=0 $
$ \Rightarrow $ $ y,(y+12)-4,(y+12)=0 $
$ \Rightarrow $ $ (y-4)(y+12)=0 $
$ \Rightarrow $ $ y=-12or4 $
Hence, x > y
BETA
