Quantitative Aptitude Ques 1262

Question: The difference between two numbers is 18 and their HCF and LCM are 6 and 168, respectively. What is the sum of squares of the two numbers? [RBI (Assistant) 2015]

Options:

A) 2280

B) 2260

C) 2420

D) 2340

E) 2380

Show Answer

Answer:

Correct Answer: D

Solution:

  • Let one number be $ x. $ Then, another number is $ x+18. $ Now, product of two numbers $ =HCF\times LCM $

$ \Rightarrow $ $ x\times (x+18)=6\times 168 $

$ \Rightarrow $ $ x^{2}+18x=1008 $

$ \Rightarrow $ $ x^{2}+18x-1008=0 $

$ \Rightarrow $ $ x^{2}-24x+42x-1008=0 $

$ \Rightarrow $ $ x(x-24)+42x(x-24)=0 $

$ \Rightarrow $ $ (x+42)(x-24)=0 $

$ \Rightarrow $ $ x=24, $ $ x\ne -42 $

$ \therefore $ Another number is 42. Required sum of squares $ ={{(24)}^{2}}+{{(42)}^{2}} $ $ =576+1764=2340 $