Quantitative Aptitude Ques 1223
Question: Directions: In each of these questions, a number series is given. In each series, only one number is wrong. Find out the wrong number. [SBI (PO) 2011]
3601, 3602, 1803, 604, 154,36,12
Options:
A) 3602
B) 1803
C) 604
D) 154
E) 36
Show Answer
Answer:
Correct Answer: D
Solution:
- $ [3601+{{(1)}^{2}}]\times 1=3602 $
$ \Rightarrow $ $ [3602+{{(2)}^{2}}\times \frac{1}{2}=1803 $
$ \Rightarrow $ $ [1803+{{(3)}^{2}}\times \frac{1}{3}=604 $
$ \Rightarrow $ $ [604+{{(4)}^{2}}+\frac{1}{4}=155\ne 154 $
$ \Rightarrow $ $ [155+{{(5)}^{2}}]\times \frac{1}{5}=36 $
$ \Rightarrow $ $ [36+{{(6)}^{2}}\times \frac{1}{6}=12 $
BETA
