Quantitative Aptitude Ques 122
Question: If the angle of elevation of a tower from a distance 100 m from its foot is $ 30{}^\circ , $ then the height of the tower is
Options:
A) $ \frac{100}{\sqrt{3}},m $
B) $ 100\sqrt{3},m $
C) $ \frac{50}{\sqrt{3}} $
D) $ 50\sqrt{3},m $
Show Answer
Answer:
Correct Answer: A
Solution:
- Let the height of tower be h m.
$ \tan 30{}^\circ =\frac{AB}{BC} $
$ \Rightarrow $ $ \frac{1}{\sqrt{3}}=\frac{h}{100} $
$ \Rightarrow $ $ h=\frac{100}{\sqrt{3}}m $
$ \therefore $ Height of the tower is $ \frac{100}{\sqrt{3}}m. $
BETA
