Quantitative Aptitude Ques 122

Question: If the angle of elevation of a tower from a distance 100 m from its foot is $ 30{}^\circ , $ then the height of the tower is

Options:

A) $ \frac{100}{\sqrt{3}},m $

B) $ 100\sqrt{3},m $

C) $ \frac{50}{\sqrt{3}} $

D) $ 50\sqrt{3},m $

Show Answer

Answer:

Correct Answer: A

Solution:

  • Let the height of tower be h m. $ \tan 30{}^\circ =\frac{AB}{BC} $
    $ \Rightarrow $ $ \frac{1}{\sqrt{3}}=\frac{h}{100} $

$ \Rightarrow $ $ h=\frac{100}{\sqrt{3}}m $

$ \therefore $ Height of the tower is $ \frac{100}{\sqrt{3}}m. $

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