Question: If two pipes function simultaneously the reservoir will be filled in 8 h one pipe fills the reservoir 12 h faster than the other. How many hours does the faster pipe take to fill the reservoir?
Options:
A) 12
B) 16
C) 14
D) 10
Show Answer
Answer:
Correct Answer: A
Solution:
- Let one pipe take x h to fill the reservoir, so that the second pipe takes $ (x-12)h. $
$ \therefore $ $ \frac{1}{x}+\frac{1}{x-12}=\frac{1}{8}, $ which is satisfied by $ x=24 $
$ \therefore $ The faster pipe takes $ (24-12)=12h $ to fill the reservoir.