Quantitative Aptitude Ques 1200
Question: In the figure given below, is parallel to MN, XY is parallel to LM and XZ is parallel to LN. Then, MY is
Options:
A) The median of $ \Delta LMN $
B) The angular bisector of $ \angle LMN $
C) Perpendicular to LN
D) Perpendicular bisector of LN
Show Answer
Answer:
Correct Answer: A
Solution:
- Since, $ ZY=MN $ and $ ZX||YN, $ $ XNYZ $ is parallelogram. $ ZX=YN $ (i) Also, $ ZX||YN, $ and $ XY||ZL, $ $ XYLZ $ is a parallelogram. $ XZ=YL $ (ii) From Eqs. (i) and (ii), we get $ YN=YL $ So, $ MY $ is a median of $ \Delta LMN\text{.} $
BETA
