Quantitative Aptitude Ques 1200

Question: In the figure given below, is parallel to MN, XY is parallel to LM and XZ is parallel to LN. Then, MY is

Options:

A) The median of $ \Delta LMN $

B) The angular bisector of $ \angle LMN $

C) Perpendicular to LN

D) Perpendicular bisector of LN

Show Answer

Answer:

Correct Answer: A

Solution:

  • Since, $ ZY=MN $ and $ ZX||YN, $ $ XNYZ $ is parallelogram. $ ZX=YN $ … (i) Also, $ ZX||YN, $ and $ XY||ZL, $ $ XYLZ $ is a parallelogram. $ XZ=YL $ … (ii) From Eqs. (i) and (ii), we get $ YN=YL $ So, $ MY $ is a median of $ \Delta LMN\text{.} $
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