Question: Find the number of ways of arranging the host and 8 guests at a circular table, so that the host always sits in a particular seat.
Options:
A) 4!
B) 8!
C) 6!
D) 9!
Show Answer
Answer:
Correct Answer: B
Solution:
- Total number of persons $ =9 $
Host can sit in a particular seat in one way.
Now, remaining position are defined relative to the host.
Hence, the remaining can sit in 8 place in $ {}^{8}P _8=8! $
$ \therefore $ The number of required arrangement $ =8!\times 1=8! $