Question: 16 children are to be divided into two group A and B of 10 and 6 children, respectively. The average marks obtained by the children of group A is 75 and that of all the children is 76. Then, the average marks of the children of group B is
Options:
A) 76
B) 77
C) 78
D) 79
Show Answer
Answer:
Correct Answer: C
Solution:
- Total marks of all children $ =16\times 76=1216 $
Total marks of children in group $ A=10\times 75=750 $
$ \because $ Total marks of children in group 8
$ =1216-750=466 $
$ \therefore $ Average marks of children of group B
$ =\frac{466}{6}=77.6\approx 78 $