Quantitative Aptitude Ques 1132
Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.
I. $ x^{2}-227=398 $
II. $ y^{2}+321=346 $
Options:
A) If $ x>y $
B) If $ x\ge y $
C) If $ x<y $
D) If $ x\le y $
E) If $ x=y $ or the relationship cannot be Established
Show Answer
Answer:
Correct Answer: E
Solution:
- I. $ x^{4}-227=398 $
$ \Rightarrow $ $ x^{4}=398+227 $
$ \Rightarrow $ $ x^{4}=625 $
$ \Rightarrow $ $ x=5, $ $ -5 $ II. $ y^{2}+321=346 $
$ \Rightarrow $ $ y^{2}=346-321 $
$ \Rightarrow $ $ y^{2}=25 $
$ \Rightarrow $ $ y=+5, $ $ -5 $
$ \therefore $ $ x=y $
BETA
