Quantitative Aptitude Ques 1132

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ x^{2}-227=398 $
II. $ y^{2}+321=346 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be Established

Show Answer

Answer:

Correct Answer: E

Solution:

  • I. $ x^{4}-227=398 $

$ \Rightarrow $ $ x^{4}=398+227 $

$ \Rightarrow $ $ x^{4}=625 $

$ \Rightarrow $ $ x=5, $ $ -5 $ II. $ y^{2}+321=346 $

$ \Rightarrow $ $ y^{2}=346-321 $

$ \Rightarrow $ $ y^{2}=25 $

$ \Rightarrow $ $ y=+5, $ $ -5 $

$ \therefore $ $ x=y $