SATHEE: Quantitative Aptitude Ques 1130

Quantitative Aptitude Ques 1130

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

I. $ x^{2}-7x+12=10 $
II. $ y^{2}+y-12=0 $

Options:

A) If $ x>y $

B) If $ x\ge y $

C) If $ x<y $

D) If $ x\le y $

E) If $ x=y $ or the relationship cannot be Established

Show Answer

Answer:

Correct Answer: B

Solution:

I. $ x^{2}-7x+12=0 $

$ \Rightarrow $ $ x^{2}-4x-3x+12=0 $

$ \Rightarrow $ $ (x-4)(x-3)=0 $

$ \Rightarrow $ $ x=4, $ $ 3 $ II. $ y^{2}+y-12=0 $

$ \Rightarrow $ $ y^{2}+4y-3y-12=0 $

$ \Rightarrow $ $ (y+4)(y-3)=0 $

$ \Rightarrow $ $ y=-4,3 $

$ \therefore $ $ x\ge y $

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Quantitative Aptitude Ques 1130

Question: Directions: In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer.

Options:

Answer:

Solution:

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