SATHEE: Quantitative Aptitude Ques 1129

Quantitative Aptitude Ques 1129

Question: The length of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, then the distance of the other chord from the centre is

Options:

A) 5 cm

B) 6 cm

C) 4 cm

D) 3 cm

Show Answer

Answer:

Correct Answer: D

Solution:

Length of smaller chord $ =6cm $

$ \therefore $ $ MB=3cm $ and $ OM=4cm $

$ \therefore $ In $ \Delta OMB, $ using Pythagoras theorem $ OB^{2}=OM^{2}+MB^{2}=9+16=25 $

$ \Rightarrow $ $ OB=5cm $ [radius of semi-circle]

$ \therefore $ $ OD=5cm $ $ [\because OB=OD] $ and $ ND=\frac{CD}{2}=\frac{8}{2}=4cm $

$ \therefore $ In $ \Delta OND, $ using Pythagoras theorem $ ON^{2}=OD^{2}-ND^{2} $

$ \Rightarrow $ $ ON^{2}=25-16=9 $

$ \Rightarrow $ $ ON^{2}=3cm $

$ \therefore $ Distance $ =3cm $

Quantitative Aptitude Ques 1128

Quantitative Aptitude Ques 1130

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