A) sum of first three quantities
B) (sum of all four quantities)/4
C) (sum of first three quantities)/3
D) (sum of first three quantities)/2
Correct Answer: C
$ \Rightarrow $ $ 3a+3b+3c+3d=4a+4b+4c $
$ \Rightarrow $ $ 3d=a+b+c $
$ \Rightarrow $ $ d=\frac{a+b+c}{3} $ = Sum of first three quantities/3