Question: One flies a kites with a thread 150 m long. If the thread of the kite makes an angle of $ 60{}^\circ $ with the horizontal line, then the height of the kite from the ground (assuming the thread to be in a straight line) is?
Options:
A) 50 m
B) $ 75\sqrt{3},m $
C) $ 25,\sqrt{3},m $
D) 80 m
Show Answer
Answer:
Correct Answer: B
Solution:
- [b] Let h be the height of kite above the ground.
In $ \Delta ABC, $ $ \sin 60{}^\circ =\frac{BC}{AB} $
$ \Rightarrow $ $ \frac{\sqrt{3}}{2}=\frac{h}{150} $
$ \Rightarrow $ $ h=\frac{\sqrt{3}\times 150}{2} $
$ \Rightarrow $ $ h=75\sqrt{3},m $