Quantitative Aptitude Ques 1063

Question: Average of n number is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is

Options:

A) $ a+\frac{{2^{n-1}}}{n} $

B) $ a+2\frac{2^{n}-1}{n} $

C) $ a+\frac{2^{n}-1}{n} $

D) $ a+\frac{{2^{n-1}}-1}{n} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • [b] New average $ =\frac{na+2+4+8+16+….+2^{n}}{n} $ $ =,\frac{na+2( \frac{2^{n}-1}{2-1} )}{n}=a+2\cdot \frac{2^{n}-1}{n} $
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