Quantitative Aptitude Ques 1055

Question: PQ is a diameter and PQRS is a cyclic quadrilateral, if $ \angle PSR=150{}^\circ , $ then measure of $ \angle RPQ $ is

Options:

A) $ 90{}^\circ $

B) $ 60{}^\circ $

C) $ 30{}^\circ $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

  • [b] In $ \Delta PRQ, $ $ \angle PRQ=90{}^\circ $ [angle in semi -circle] and $ \angle RQP=30{}^\circ $ [opposite angle] In $ \Delta PRQ, $ $ \angle PRQ+\angle RPQ+\angle RQP=180{}^\circ $ $ \angle RPQ=180{}^\circ -120{}^\circ =60{}^\circ $
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