Question: The minimum value of $ 2{{\sin }^{2}}\theta +3{{\cos }^{2}}\theta $ is
Options:
A) 0
B) $ 3 $
C) $ 2 $
D) $ 1 $
Show Answer
Answer:
Correct Answer: B
Solution:
- $ 2{{\sin }^{2}}\theta +3{{\cos }^{2}}\theta =2{{\sin }^{2}}\theta +2{{\cos }^{2}}\theta +{{\cos }^{2}}\theta $
$ =2({{\sin }^{2}}\theta +{{\cos }^{2}}\theta )+{{\cos }^{2}}\theta $
$ =2+{{\cos }^{2}}\theta $
$ \because $ Minimum value of $ \theta =-1 $
$ \therefore $ Required minimum value $ =2+{{(-1)}^{2}}=2+1=3 $