Quantitative Aptitude Ques 1040

Question: A liquid P is $ 1\frac{3}{7} $ times as heavy as water and water is $ 1\frac{2}{5} $ times as heavy as another liquid Q. The amount of liquid P that must be added to 7 L of the liquid Q, so that the mixture may weight as much as an equal volume of water will be

Options:

A) $ 7L $

B) $ 5\frac{1}{6}L $

C) $ 5L $

D) $ 4\frac{2}{3}L $

Show Answer

Answer:

Correct Answer: D

Solution:

  • Let x L of liquid P be mixed to 7 L of Q. According to the question, $ x\times \frac{10}{7}+\frac{5}{7}\times 7=x+7 $

$ \Rightarrow $ $ 10x+35=7x+49 $
$ \Rightarrow $ $ 3x=14 $

$ \Rightarrow $ $ x=\frac{14}{3}=4\frac{2}{3}L $