SATHEE: Quantitative Aptitude Ques 1036

Quantitative Aptitude Ques 1036

Question: If $ a^{2}+b^{2}+2b+4a+5=0, $ then the value of $ \frac{a-b}{a+b} $ is

Options:

A) $ 3 $

B) $ -3 $

C) $ \frac{1}{3} $

D) $ -\frac{1}{3} $

Show Answer

Answer:

Correct Answer: C

Solution:

Given, $ a^{2}+b^{2}+2b+4a+5=0 $

$ \Rightarrow $ $ a^{2}+4a+b^{2}+2b+5=0 $

$ \Rightarrow $ $ a^{2}+4a+4+b^{2}+2b+1=0 $

$ \Rightarrow $ $ {{(a+2)}^{2}}+{{(b+1)}^{2}}=0 $ $ [\because {{(a+b)}^{2}}=a^{2}+b^{2}+2ab] $ It is possible only, when $ a+2=0 $
$ \Rightarrow $ $ a=-2 $ and $ b+1=0 $
$ \Rightarrow $ $ b=-1 $

$ \therefore $ $ \frac{a-b}{a+b}=\frac{-2+1}{-2-1}=\frac{-1}{-3}=\frac{1}{3} $

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Quantitative Aptitude Ques 1036

Question: If $ a^{2}+b^{2}+2b+4a+5=0, $ then the value of $ \frac{a-b}{a+b} $ is

Options:

Answer:

Solution:

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