OO’ = 12 cm and AB = 16 cm, then the radius of the circles is
A) 10 cm
B) 8 cm
C) 12 cm
D) 14 cm
Correct Answer: A
$ \therefore $ $ AC=BC=8cm $ and $ OO’=12cm $
$ \therefore $ $ OC=CO’=6cm $ In $ \Delta OAC, $ by Pythagoras theorem, $ OA=\sqrt{OC^{2}+CA^{2}}=\sqrt{6^{2}+8^{2}} $ $ =\sqrt{36+64}=\sqrt{100}=10cm $