सरलीकरण प्रश्न 7
प्रश्न-
$(?)^{3}=4913$
(1) 27
(2) 19
(3) 17
(4) 29
(5) इनमें से कोई नहीं
Show Answer
सही उत्तर: (3)
हल: (3)
$ ?=\sqrt[3]{4913}=\sqrt[3]{17 \times 17 \times 17}=17 $
BETA
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