समीकरण और असमानता प्रश्न 185
I. (3 x^{2}-13 x+12=0)
II. (2 y^{2}-15 y+28=0)
(1) (x>y)
(2) (x \geq y)
(3) (x<y)
(4) relationship between (x) and (y) cannot be determined
(5) (x \leq y)
Show Answer
Correct Answer: 185.(3)
Solution: (3) I. (3 x^{2}-13 x+12=0)
(\Rightarrow 3 x^{2}-4 x-9 x+12=0)
(\Rightarrow x(3 x-4)-3(3 x-4)=0)
(\Rightarrow(x-3)(3 x-4)=0)
(\Rightarrow x=3) or, (\frac{4}{3})
II. (2 y^{2}-15 y+28=0)
(\Rightarrow 2 y^{2}-7 y-8 y+28=0)
(\Rightarrow y(2 y-7)-4(2 y-7)=0)
(\Rightarrow(y-4)(2 y-7)=0)
(\Rightarrow y=4) or, (\frac{7}{2})
Clearly, (x<y)
BETA
